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【ACM】ACM steps 1.1.4*

A+B for Input-Output Practice (IV)

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 25266 Accepted Submission(s): 13962

Problem Description
Your task is to Calculate the sum of some integers.

Input
Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.

Output
For each group of input integers you should output their sum in one line, and with one line of output for each line in input.

Sample Input
4 1 2 3 4
5 1 2 3 4 5
0

Sample Output
10
15

参考题解:

#include 
int main()
{
    int n,sum,i,t;
    while(scanf("%d",&n)!=EOF)
    {
        if(n==0) break;
            sum=0;
        for(i=0;i<n;i++)
        {
            scanf("%d",&t);
            sum=sum+t;
        }
        printf("%dn",sum);
    }
}

!=EOF的作用就是一直读到文件的末尾,还有就是要注意if(n==0) break;要直接放在while语句的下面。且这个语句后面要加分号。


原文标题:【ACM】ACM steps 1.1.4*|落絮飞雁的个人网站
原文链接:https://www.luoxufeiyan.com/2013/10/26/%e3%80%90acm%e3%80%91acm-steps-1-1-4/
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